It will be 1360 * 1 / (0.0057*0.0057) = 41.8 MWm/2 assuming the Earth is at 1AU.
Strictly speaking (and one should always speak strictly, especially to animals and young children) the figure must be multiplied by the albedo as some of that power density will be reflected. I have little idea of the true albedo integrated over all wavelengths but a figure of 0.9 may be in the right ballpark. Still a fearsome figure.